4(iii)
A chloride of iron 'R', when treated with sodium hydroxide gives P and Q as a product. Q is a reddish-brown precipitate.
(a) Identify R.
(b) State the formula of the compounds P and Q formed after the reaction.
(c) What do you observe when excess NaOH is added to Q?
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(a) R is ferric chloride (iron(III) chloride), FeCl3.
(b) P is NaCl and Q is Fe(OH)3.
FeCl3 + 3NaOH ⟶ Fe(OH)3 ↓ + 3NaCl
(c) On adding excess sodium hydroxide, the reddish-brown precipitate of Fe(OH)3 remains insoluble, i.e., there is no change.