1(xiv)
The ratio between the volumes occupied by 22 grams of carbon dioxide and 10 grams of hydrogen gas is:
- (a)2.2 :1
- (b)1: 2.2
- (c)1:10
- (d)10:1
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1:10
Reason — Molar mass of CO2 = 12 + 2 x 16 = 44 g/mole
∴ Moles of 22g CO2 = $\frac{22}{44}$ = 0.5
Molar mass of H2 = 2 x 1 = 2 g/mole
∴ Moles of 10g H2 = $\frac{10}{2}$ = 5
Under the same conditions of temperature and pressure, the volume of a gas is directly proportional to the number of moles. Therefore, the volume ratio will be the same as the mole ratio.
Volume ratio = $\frac{\text{Vol. of CO}_2}{\text{Vol. of H}_2}$ = $\frac{0.5}{5}$ = 1 : 10