Which of the following will occupy the volume 2.8 litres at S.T.P.? (Atomic weight: C = 12, O = 16, Cl = 35.5, S = 32)

8 g of sulphur dioxide

Reason — One mole of any gas occupies 22.4 litres of volume at S.T.P.

The required moles of gas at S.T.P = $\frac{2.8}{22.4}$ = 0.125 mol

Substance	Molar mass(g)	Given mass (moles/g)	No. of moles	Volume at STP (L)
2 moles of carbon dioxide	44	2 mol	2	44.8
7.1 g of chlorine	71	7.1 g	0.10	2.24
8 g of sulphur dioxide	64	8g	0.125	2.8
56 g of carbon monoxide	28	56g	2.00	44.8

∴ 8 g of sulphur dioxide will occupy the volume 2.8 litres at S.T.P.