1(x)
An alkane with molecular mass 44 is:
- (a)CH4
- (b)C3H8
- (c)C4H10
- (d)C2H6
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C3H8
Reason — Let's check the molecular masses:
- CH4 → 12 + 4×1 = 16
- C2H6 → 2×12 + 6×1 = 24 + 6 = 30
- C3H8 → 3×12 + 8×1 = 36 + 8 = 44
- C4H10 → 4×12 + 10×1 = 48 + 10 = 58
So, the alkane with molecular mass 44 is C3H8 (propane).