The empirical formula of an organic compound is C 3 H 4 N. Its molecular weight is 108. Find the amount of carbon in one mole of the compound. Show all the…

Empirical formula is C₃H₄N

Empirical formula weight = (3 x 12) + (4 x 1) + (1 x 14)
= 36 + 4 + 14
= 54

Molecular weight = 108

Multiplying Factor (n) = $\frac{\text{Molecular weight}}{\text{Empirical formula weight}}$

n = $\frac{108}{54} = 2$

∴ Molecular formula = (C₃H₄N) x 2 = C₆H₈N₂

No. of carbon atoms in 1 mole of C₆H₈N₂ = 6

∴ Mass of carbon in one mole of the compound (C₆H₈N₂) = 6 x 12 = 72 g

Hence, in 1 mole of the compound (C₆H₈N₂), there is 72 grams of carbon.