7(iii)
Ammonia burns in oxygen as shown below.
4NH3 + 3O2 ⟶ 2N2 + 6H2O
If 240 cc of ammonia is burnt in 300 cc of oxygen, find out the composition of the resultant gaseous mixture at room temperature.
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According to the given equation:
For N2
4 vol. of NH3 produce 2 vol. of N2
∴ 240 cc of NH3 will produce = $\frac{2 \times 240}{4}$ = 120 cc of N2
For O2
4 vol. of NH3 reacts with 3 vol. of O2
∴ 240 cc of NH3 will react with = $\frac{3 \times 240}{4}$ = 180 cc of O2.
Amount of unused Oxygen = 300 cc - 180 cc = 120 cc
Hence, composition of the resultant gaseous mixture at room temperature is 120 cc of O2 + 120 cc of N2