6(ii)
The Empirical formula of an organic compound is CHCl2.
If its relative molecular mass is 168, what is its molecular formula?
[At. Wt. C = 12, H = 1, Cl = 35.5]
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Empirical formula is CHCl2
Empirical formula weight = 12 + 1 + 2[35.5] = 12 + 1 + 71 = 84
Molecular weight = 168
$$\begin{aligned}\text{n} = \frac{\text{Molecular weight}}{\text{Empirical formula weight}} \\[0.5em] = \frac{168}{84} = 2\end{aligned}$$
So, molecular formula = 2(CHCl2) = C2H2Cl4