In the circuit given below, identify the correct relation between the currents flowing through the 2 Ω, 3 Ω, and 5 Ω resistors:

current through 2Ω = current through 5Ω

Reason —

Given,

Emf of the cell (ε) = 12 V

As, same current flows through 3 Ω and 2 Ω resistances so they are connected in series and their net resistance will be :

R_S = 2 + 3 = 5 Ω

Since, R_S and 5 Ω have same potential difference so they are in parallel combination.

As resistance in both the arms is the same (5 Ω) so equal current flows through (3 Ω + 2 Ω) combination and 5 Ω.

Hence, current through 2Ω = current through 5Ω.