If three equal forces F 1 , F 2 and F 3 are acting at the end A of the rod AB, pivoted at the center O, as shown in the diagram given below, then the moment of…

ICSE Class 10 Physics PYQ · 2026 Improvement · Section A

1(iv)1 Mark · 2026 · Section A · 2026 Improvement

If three equal forces F1, F2 and F3 are acting at the end A of the rod AB, pivoted at the center O, as shown in the diagram given below, then the moment of force is:

If three equal forces F 1, F 2 and F 3 are acting at the end A of the rod AB, pivoted at the center O, as shown in the diagram given below, then the moment of force is:. Improvent Board Paper 2026, ICSE 2026 Improvent Physics Solved Question Paper.
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least for F3 and maximum for F1

Reason — The moment of a force is the product of the force and the perpendicular distance of its line of action from the pivot. If a force F acts at A at an angle θ with the rod and OA = r, then

$\tau = \text{F r}\sin \theta$

All the three forces are equal and act at the same point A, so the moment of each depends only on the angle θ.

F3 acts along the rod, so θ = 0° and its line of action passes through O, giving τ3 = 0, the least.

F1 acts perpendicular to the rod, so θ = 90° and τ1 = F r, the maximum.

F2 acts at an angle between 0° and 90°, so its moment lies between the two.

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