If three equal forces F1, F2 and F3 are acting at the end A of the rod AB, pivoted at the center O, as shown in the diagram given below, then the moment of force is:

- (a)least for F2 and maximum for F1
- (b)least for F1 and maximum for F3
- (c)least for F3 and maximum for F1
- (d)least for F2 and maximum for F3
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least for F3 and maximum for F1
Reason — The moment of a force is the product of the force and the perpendicular distance of its line of action from the pivot. If a force F acts at A at an angle θ with the rod and OA = r, then
$\tau = \text{F r}\sin \theta$
All the three forces are equal and act at the same point A, so the moment of each depends only on the angle θ.
F3 acts along the rod, so θ = 0° and its line of action passes through O, giving τ3 = 0, the least.
F1 acts perpendicular to the rod, so θ = 90° and τ1 = F r, the maximum.
F2 acts at an angle between 0° and 90°, so its moment lies between the two.