6(iii)
Given are two pulleys.
(a) Copy and complete the labelled diagram connecting the two pulleys with a tackle to obtain Velocity Ratio = 2.
(b) If Load = 48 kgf and efficiency is 80% then calculate :
- (a)Mechanical Advantage.
- (b)Effort needed to lift the load
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(a) The diagram is given below :
(b)
- Given,
Velocity Ratio = 2
Load = 48 kgf
Efficiency = 80% = 0.8
As,
$$\begin{aligned}\text {Efficiency} = \frac {\text {Mechanical Advantage}}{\text {Velocity Ratio}}\\[1 em] ⇒ \text {Mechanical Advantage} = \text {Efficiency} \times \text {Velocity Ratio}=0.8 \times 2 = 1.6\end{aligned}$$
- As,
$$\begin{aligned}\text {Mechanical Advantage} = \frac{\text {Load}}{\text {Effort}}\\[1 em] ⇒ \text {Effort} = \frac{\text {Load}}{\text {Mechanical Advantage}}= \frac{48}{1.6}=30 \text { kgf}\end{aligned}$$