Copy and complete the nuclear reaction by filling in the blanks.
$_{92}\text{U}^{235} + _0\text n^1 \longrightarrow _{56}\text {Ba}^{\cdots} + \space _{\cdots}\text {Kr}^{92} + 3 \space _0\text n^1$
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As only neutrons are involved in the reaction which number of protons and total nucleon number (i.e., number of protons + neutrons) remain constant.
Then,
Initially,
No. of protons (np) = Atomic number of $_{92}\text{U}^{235}$ = 92
No. of nucleons (n) = Mass number of $_{92}\text{U}^{235}$ + mass number of $_0\text n^1$ = 235 + 1 = 236
Now,
Finally,
Let atomic number of Kr is Z and mass number of Ba is A.
No. of protons (np) = Atomic number of $_{56}\text{Ba}^{\text A}$ + Atomic number of $_{\text Z}\text{Kr}^{92}$ = 56 + Z
and
No. of nucleons (n) = mass number of $_{56}\text{Ba}^{\text A}$ + mass number of $_{\text Z}\text{Kr}^{92}$ + 3 x mass number of $_0\text n^1$ = A + 92 + 3 = A + 95
As number of protons are constant :
⇒ 92 = 56 + Z
⇒ Z = 92 - 56 = 36
Also, number of nucleons are constant :
⇒ 236 = A + 95
⇒ A = 236 - 95 = 141
So reaction will be :
$_{92}\text{U}^{235} + _0\text{n}^1 \longrightarrow _{56}\text {Ba}^{141} + \space _{36}\text {Kr}^{92} + 3 \space _0\text n^1$