1(d)
If the power of a motor be 100 kW, at what speed can it raise a load of 50,000 N?
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Given, power P = 100 kW = 100 x 103 W, force F = 50,000 N
Power P = Force (F) x Speed (v)
Substituting the values we get,
$$\begin{aligned}100 \times 10^3 = 50,000 \times v \\[0.5em] \Rightarrow v = \frac{100 \times 10^3 }{50,000} \\[0.5em] \Rightarrow v = 2 m s^{-1}\end{aligned}$$