Graphical Representation (Histograms & Ogives)

ICSE Class 10 Mathematics · Selina Concise Mathematics · 17 solved questions

Exercise
1(a)Exercise 23

From the given table the values of a, b and c are :

C.I.FrequencyCumulative
Frequency
30-402424
40-50a40
50-6012b
60-70c60
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From table,

⇒ 24 + a = 40

⇒ a = 40 - 24 = 16

⇒ b = 40 + 12 = 52

⇒ b + c = 60

⇒ 52 + c = 60

⇒ c = 60 - 52 = 8.

Hence, Option 1 is the correct option.

1(b)Exercise 23

The cumulative frequency of the class 70-90 is :

The cumulative frequency of the class 70-90 is : Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
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From the graph, we form the cumulative frequency table :

ClassFrequencyCumulative frequency
30-505050
50-703080 (50 + 30)
70-9040120 (80 + 40)
90-11060180 (120 + 60)

Hence, Option 2 is the correct option.

1(c)Exercise 23

For the given frequency distribution, the adjustment factor is :

C.I.f
30-348
34-3810
38-428
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By formula,

Adjustment factor = $\frac{\text{Lower limit of one class - Upper limit of previous class}}{2}$

The given classes (30-34, 34-38, 38-42) are already in continuous (exclusive) form, as the upper limit of each class is equal to the lower limit of the next class.

⇒ Adjustment factor = $\frac{34 - 34}{2} = \frac{0}{2} = 0$.

Hence, Option 3 is the correct option.

1(d)Exercise 23

The cumulative frequency curve for a frequency distribution starts from :

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The cumulative frequency curve for a frequency distribution starts from lower limit of 1st class.

Hence, Option 3 is the correct option.

1(e)Exercise 23

The cumulative frequency curve for a frequency distribution terminates at :

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The cumulative frequency curve for a frequency distribution terminates at upper limit of last class.

Hence, Option 4 is the correct option.

2(i)Exercise 23

Draw histograms for the following frequency distributions :

Class intervalFrequency
0 - 1012
10 - 2020
20 - 3026
30 - 4018
40 - 5010
50 - 606
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Steps of construction of histogram :

  1. Take 2 cm along x-axis = 10 units.

  2. Take 1 cm along y-axis = 5 units.

  3. Construct rectangles corresponding to the above continuous frequency distribution table.

The required histogram is shown in the below figure:

Draw histograms for the following frequency distributions. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
2(ii)Exercise 23

Draw histograms for the following frequency distributions :

Class intervalFrequency
10 - 1615
16 - 2223
22 - 2830
28 - 3420
34 - 4016
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Steps of construction of histogram :

  1. Since, the scale on x-axis starts at 10, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 10.

  2. Take 2 cm along x-axis = 6 units.

  3. Take 1 cm along y-axis = 5 units.

  4. Construct rectangles corresponding to the above continuous frequency distribution table.

The required histogram is shown in the below figure:

Draw histograms for the following frequency distributions. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
2(iii)Exercise 23

Draw histograms for the following frequency distributions :

Class markFrequency
168
2412
3215
4018
4825
5619
6410
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Since, the difference between the values of any two consecutive class marks is 8 (24 - 16).

Therefore, subtract $\frac{8}{2}$ = 4, from each class mark to get the lower limit of the corresponding class interval and add 4 to each class mark to get the upper limit.

Frequency distribution table :

Class markClassFrequency
1612 - 2008
2420 - 2812
3228 - 3615
4036 - 4418
4844 - 5225
5652 - 6019
6460 - 6810

Steps of construction of histogram :

  1. Since, the scale on x-axis starts at 12, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 12.

  2. Take 1 cm along x-axis = 8 units.

  3. Take 1 cm along y-axis = 5 units.

  4. Construct rectangles corresponding to the above continuous frequency distribution table.

The required histogram is shown in the below figure:

Draw histograms for the following frequency distributions. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
3(i)Exercise 23

Draw a cumulative frequency curve (ogive) for the following distributions :

Class IntervalFrequency
10 - 1510
15 - 2015
20 - 2517
25 - 3012
30 - 3510
35 - 408
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The cumulative frequency distribution :

Class IntervalFrequencyCumulative frequency
10 - 151010
15 - 201525 (10 + 15)
20 - 251742 (25 + 17)
25 - 301254 (42 + 12)
30 - 351064 (54 + 10)
35 - 40872 (64 + 8)

Steps of construction of ogive :

  1. Take 2 cm = 5 units along x-axis.

  2. Take 1 cm = 10 units along y-axis.

  3. Ogive always starts from a point on x-axis representing the lower limit of the first class. Mark point (10, 0).

  4. Take upper class limits along x-axis and corresponding cumulative frequencies along y-axis, mark the points (15, 10), (20, 25), (25, 42), (30, 54), (35, 64) and (40, 72).

  5. Join the points marked by a free hand curve.

The required ogive is shown in the below figure:

Draw a cumulative frequency curve (ogive) for the following distributions. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
3(ii)Exercise 23

Draw a cumulative frequency curve (ogive) for the following distributions :

Class intervalFrequency
10 - 1923
20 - 2916
30 - 3915
40 - 4920
50 - 5912
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The above distribution is discontinuous converting into continuous distribution, we get :

Adjustment factor = (Lower limit of one class - Upper limit of previous class) / 2

= $\frac{20 - 19}{2} = \frac{1}{2}$

= 0.5

Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.

Classes before adjustmentClasses after adjustmentFrequencyCumulative frequency
10 - 199.5 - 19.52323
20 - 2919.5 - 29.51639 (23 + 16)
30 - 3929.5 - 39.51554 (39 + 15)
40 - 4939.5 - 49.52074 (54 + 20)
50 - 5949.5 - 59.51286 (74 + 12)

Steps of construction of ogive :

  1. Since, the scale on x-axis starts at 9.5, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 9.5.

  2. Take 2 cm = 10 units along x-axis.

  3. Take 1 cm = 10 units along y-axis.

  4. Ogive always starts from a point on x-axis representing the lower limit of the first class. Mark point (9.5, 0).

  5. Take upper class limits along x-axis and corresponding cumulative frequencies along y-axis, mark the points (19.5, 23), (29.5, 39), (39.5, 54), (49.5, 74) and (59.5, 86).

  6. Join the points marked by a free hand curve.

The required ogive is shown in the below figure:

Draw a cumulative frequency curve (ogive) for the following distributions. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
4(i)Exercise 23

Draw an ogive for the following distribution :

Marks obtainedNo. of students
less than 108
less than 2025
less than 3038
less than 4050
less than 5067
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Cumulative frequency distribution table :

Marks obtainedClass intervalNo. of students (Cumulative frequency)
less than 100 - 108
less than 2010 - 2025
less than 3020 - 3038
less than 4030 - 4050
less than 5040 - 5067

Steps of construction of ogive :

  1. Take 2 cm = 10 units along x-axis.

  2. Take 1 cm = 10 units along y-axis.

  3. Ogive always starts from a point on x-axis representing the lowest limit. Mark point (0, 0).

  4. Take upper class limits along x-axis corresponding cumulative frequencies along y-axis, mark the points (10, 8), (20, 25), (30, 38), (40, 50) and (50, 67).

  5. Join the points marked by a free hand curve.

The required ogive is shown in the below figure:

Draw an ogive for the following distribution. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
4(ii)Exercise 23

Draw an ogive for the following distribution :

Age in years (less than)Cumulative frequency
100
2017
3032
4037
5053
6058
7065
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Cumulative frequency distribution table :

Age in years (less than)Cumulative frequency
100
2017
3032
4037
5053
6058
7065

Steps of construction of ogive :

  1. Take 2 cm = 10 units along x-axis.

  2. Take 1 cm = 10 units along y-axis.

  3. Ogive always starts from a point on x-axis representing the lowest limit. Mark point (0, 0).

  4. Take upper class limits along x-axis corresponding cumulative frequencies along y-axis, mark the points (10, 0), (20, 17), (30, 32), (40, 37), (50, 53), (60, 58) and (70, 65).

  5. Join the points marked by a free hand curve.

The required ogive is shown in the adjoining figure.

Draw an ogive for the following distribution. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
5Exercise 23

(a) Use the information given in the adjoining histogram to construct a frequency table.

(b) Use this table to construct an ogive.

(a) Use the information given in the adjoining histogram to construct a frequency table. (b) Use this table to construct an ogive. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
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(a) The cumulative frequency table for above distribution is :

Class intervalFrequencyCumulative frequency
8 - 1299
12 - 161625
16 - 202247
20 - 241865
24 - 281277
28 - 32481

(b) Steps of construction of ogive :

  1. Since, the scale on x-axis starts at 8, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 8.

  2. Take 2 cm = 4 units along x-axis.

  3. Take 1 cm = 10 units along y-axis.

  4. Ogive always starts from a point on x-axis representing the lowest limit. Mark point (8, 0).

  5. Take upper class limits along x-axis corresponding cumulative frequencies along y-axis, mark the points (12, 9), (16, 25), (20, 47), (24, 65), (28, 77) and (32, 81).

  6. Join the points marked by a free hand curve.

The required ogive is shown in the adjoining figure.

(a) Use the information given in the adjoining histogram to construct a frequency table. (b) Use this table to construct an ogive. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
6Exercise 23

Use graph paper for this question.

The table given below shows the monthly wages of some factory workers.

(i) Using the table, calculate the cumulative frequencies of workers.

(ii) Draw a cumulative frequency curve.

Wages (in ₹)No. of workers
6500 - 700010
7000 - 750018
7500 - 800022
8000 - 850025
8500 - 900017
9000 - 950010
9500 - 100008
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(i) The cumulative frequency distribution table is as follows :

Wages (in ₹)No. of workersCumulative frequency
6500 - 70001010
7000 - 75001828 (10 + 18)
7500 - 80002250 (28 + 22)
8000 - 85002575 (50 + 25)
8500 - 90001792 (75 + 17)
9000 - 950010102 (92 + 10)
9500 - 100008110 (102 + 8)

(ii) Steps for construction of cumulative frequency curve :

  1. Since, the scale on x-axis starts at 6500, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 6500.

  2. Take 2 cm along x-axis = ₹ 500.

  3. Take 1 cm along y-axis = 10 workers.

  4. Ogive always starts from a point on x-axis representing the lower limit of first class. Mark point (6500, 0).

  5. Take upper class limits along x-axis, corresponding cumulative frequencies along y-axis, mark the points (7000, 10), (7500, 28), (8000, 50), (8500, 75), (9000, 92), (9500, 102) and (10000, 110).

  6. Join the points marked by a free hand curve.

The required ogive is shown in the below figure:

Use graph paper for this question. The table given below shows the monthly wages of some factory workers. (i) Using the table, calculate the cumulative frequencies of workers. (ii) Draw a cumulative frequency curve. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
7Exercise 23

The following table shows the distribution of the heights of a group of factory workers :

Ht. (cm)No. of workers
150 - 1556
155 - 16012
160 - 16518
165 - 17020
170 - 17513
175 - 1808
180 - 1856

(i) Determine the cumulative frequencies.

(ii) Draw the 'less than' cumulative frequency curve on graph paper.

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(i) The cumulative frequency distribution table is as follows :

Ht. (cm)No. of workersCumulative frequency
150 - 15566
155 - 1601218 (6 + 12)
160 - 1651836 (18 + 18)
165 - 1702056 (36 + 20)
170 - 1751369 (56 + 13)
175 - 180877 (69 + 8)
180 - 185683 (77 + 6)

(ii) Steps for construction of 'less than' cumulative frequency curve :

  1. Since, the scale on x-axis starts at 150, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 150.

  2. Take 2 cm along x-axis = 5 cm.

  3. Take 1 cm along y-axis = 10 workers.

  4. Ogive always starts from a point on x-axis representing the lower limit of first class. Mark point (150, 0).

  5. Take upper class limits along x-axis, corresponding cumulative frequencies along y-axis, mark the points (155, 6), (160, 18), (165, 36), (170, 56), (175, 69), (180, 77) and (185, 83).

  6. Join the points marked by a free hand curve.

The required ogive is shown in the below figure:

The following table shows the distribution of the heights of a group of factory workers. (i)Determine the cumulative frequencies. (ii) Draw the 'less than' cumulative frequency curve on graph paper. Graphical Representation, Concise Mathematics Solutions ICSE Class 10.
8(i)Exercise 23

Construct a frequency distribution table for the following distribution :

Marks (less than)Cumulative frequency
00
107
2028
3054
4071
5084
60105
70147
80180
90196
100200
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The frequency distribution table for above distribution is :

MarksCumulative frequencyFrequency
0 - 1077
10 - 202821 (28 - 7)
20 - 305426 (54 - 28)
30 - 407117 (71 - 54)
40 - 508413 (84 - 71)
50 - 6010521 (105 - 84)
60 - 7014742 (147 - 105)
70 - 8018033 (180 - 147)
80 - 9019616 (196 - 180)
90 - 1002004 (200 - 196)
8(ii)Exercise 23

Construct a frequency distribution table for the following distribution :

Marks (more than)Cumulative frequency
0100
1087
2065
3055
4042
5036
6031
7021
8018
907
1000
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The frequency distribution table for above distribution is :

MarksCumulative frequencyFrequency
0 - 1010013 (100 - 87)
10 - 208722 (87 - 65)
20 - 306510 (65 - 55)
30 - 405513 (55 - 42)
40 - 50426 (42 - 36)
50 - 60365 (36 - 31)
60 - 703110 (31 - 21)
70 - 80213 (21 - 18)
80 - 901811 (18 - 7)
90 - 10077

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