1(xv)
A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the numbers 1, 2, 3……12. The probability that it will point to an odd number is :
- (a)$\frac{1}{6}$
- (b)$\frac{1}{12}$
- (c)$\frac{1}{2}$
- (d)$\frac{5}{12}$
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Given,
The arrow can come to rest pointing to one of the numbers 1, 2, 3, ......, 12.
Total number of possible outcomes = 12
Favourable outcomes = Arrow pointing to an odd number
{1, 3, 5, 7, 9, 11}
Number of favourable outcomes = 6
By formula,
Probability = $\frac{\text{No. of favourable outcomes}}{\text{Total number of outcomes}}$
= $\frac{6}{12}$
= $\frac{1}{2}$.
Hence, option 3 is the correct option.