1(i)
When polynomial x3 - 3x2 - 6x + 8 is divided by (x + 2), the remainder is zero. The probability of (x + 2) to be one of the factors of the given polynomial is:
- (a)0
- (b)$\frac{1}{3}$
- (c)$\frac{2}{3}$
- (d)1
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Since, on dividing x3 - 3x2 - 6x + 8 by (x + 2), the remainder is zero.
Thus, (x + 2) is the polynomial of x3 - 3x2 - 6x + 8.
∴ The probability of (x + 2) to be one of the factors of the polynomial = 1.
Hence, option 4 is the correct option.