1(vi)
The table shows the values of x and y, where x is proportional to y. What are the values of M and N ?
| x | y |
|---|---|
| 6 | M |
| 12 | 18 |
| N | 6 |
- (a)M = 4, N = 9
- (b)M = 9, N = 3
- (c)M = 9, N = 4
- (d)M = 12, N = 0
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Given, x is proportional to y.
$$\begin{aligned}\Rightarrow \frac{6}{M} = \frac{12}{18} \\[1em] \Rightarrow M = \frac{6 \times 18}{12} \\[1em] \Rightarrow M = \frac{108}{12} \\[1em] \Rightarrow M = 9. \\[1.5em] \frac{12}{18} = \frac{N}{6} \\[1em] \Rightarrow N = \frac{12 \times 6}{18} \\[1em] \Rightarrow N = \frac{72}{18} \\[1em] \Rightarrow N = 4.\end{aligned}$$
Hence, Option 3 is the correct option.