If the roots of equation x 2 - 6x + k = 0 are real and distinct, then value of k is :

Given,

Roots of equation x² - 6x + k = 0 are real and distinct.

∴ D > 0

⇒ b² - 4ac > 0

⇒ (-6)² - 4 × 1 × k > 0

⇒ 36 - 4k > 0

⇒ 4k < 36

⇒ k < $\frac{36}{4}$

⇒ k < 9.

Hence, Option 4 is the correct option.