1(v)
If 3 is a root of the quadratic equation x2 - px + 3 = 0 then p is equal to :
- (a)4
- (b)3
- (c)5
- (d)2
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Given,
3 is a root of the quadratic equation x2 - px + 3 = 0
∴ 32 - 3p + 3 = 0
⇒ 9 - 3p + 3 = 0
⇒ 12 - 3p = 0
⇒ 3p = 12
⇒ p = $\frac{12}{3}$ = 4.
Hence, Option 1 is the correct option.