Periodic Table

ICSE Class 10 Chemistry · Viraf J Dalal Chemistry · 130 solved questions

Exercise
Marks
12016

Select the correct answer from A, B, C and D — An element with the atomic number 19 will most likely combine chemically with the element whose atomic number is:

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17

Reason — The element with atomic number 19 has electronic configuration of (2, 8, 8, 1) and that with atomic number 17 has electronic configuration of (2, 8, 7). This element with atomic number 17 needs 1 electron to complete its octet whereas element with atomic number 19 has an extra electron. Hence, an element with atomic number 19 is most likely to combine with the element with atomic number 17.

22016

Identify the term :

(i) The tendency of an atom to attract electrons to itself when combined in a compound.

(ii) The electrons present in the outermost shell of an atom.

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(i) Electronegativity.

(ii) Valence Electrons.

32016

Write the correct symbol > (greater than) or < (less than) in the statements :

(i) The ionization potential of potassium is ............... that of sodium.

(ii) The electronegativity of iodine is ............... that of chlorine.

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(i) The ionization potential of potassium is < (less than) that of Sodium.

(ii) The electronegativity of iodine is < (less than) that of chlorine.

42016

Use the letters only written in the Periodic Table given below to answer the questions :

 IIIIIIIVVVIVIIO
1       L
2Q EGJZM 
3R       
4T       

(i) State the number of valence electrons in atom J.

(ii) Which element shown forms ions with a single negative charge?

(iii) Which metallic element is more reactive than R?

(iv) Which element has it's electrons arranged in four shells?

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(i) Atom J has 5 valence electrons as it belongs to the fifth group in the periodic table.

(ii) M forms ions with a single negative charge as it has 7 electrons in the valence shell and obtaining one more electron completes it's octet.

(iii) Metal T is more reactive than R because elements at the bottom of the group are more reactive.

(iv) T has it's electrons arranged in 4 shells as it belongs to 4th period.

52016

Fill in the blanks :

(i) If an element has a low ionization energy then it is likely to be .......... (metallic/non metallic).

(ii) If an element has seven electrons in it's outermost shell then it is likely to have the .......... (largest/smallest) atomic size among all the elements in the same period.

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(i) If an element has a low ionization energy then it is likely to be metallic.

(ii) If an element has seven electrons in it's outermost shell then it is likely to have the smallest atomic size among all the elements in the same period.

12017

Select the correct answer — The energy required to remove an electron from a neutral isolated gaseous atom and convert it into a positively charged gaseous ion is called .......... (electron affinity, ionization potential, electronegativity)

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Ionization Potential

22017

Match the atomic number 2, 4, 8, 15 and 19 with the following:

(i) A solid non-metal in the third period.

(ii) A metal of valency 1.

(iii) A gaseous element with valency 2.

(iv) An element in Group 2.

(v) A rare gas.

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(i) 15

(ii) 19

(iii) 8

(iv) 4

(v) 2

32017

Arrange as per the instruction :

(i) He, Ar, Ne (Increasing order of the number of electron shells)

(ii) Na, Li, K (Increasing ionization energy)

(iii) F, Cl, Br (Increasing electronegativity)

(iv) Na, K, Li (Increasing atomic size).

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(i) He < Ne < Ar

Reason — Number of electron shells increases as we move down the group.

(ii) K < Na < Li

Reason — Ionization potential decreases as we move down the group.

(iii) Br < Cl < F

Reason — Electronegativity decreases as we move down the group.

(iv) Li < Na < K

Reason — Atomic Size increases as we move down the group.

12018

Give one word or a phrase for the following statement: The energy released when an electron is added to a neutral gaseous isolated atom to form a negatively charged ion.

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Electron affinity

22018

Give reasons :

(i) Inert gases do not form ions.

(ii) Ionization potential increases across a period — left to right.

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(i) Inert gases have completely filled octet which makes them extremely stable. They neither lose, nor gain electrons. Hence, they do not form ions.

(ii) The ionization potential of an element increases across a period because the atomic size decreases due to an increase in nuclear charge and electrons in the outermost shell are more strongly held because of which greater energy is required to remove the electron.

32018

In Period 3 of the Periodic Table, element B is placed to the left of element A. On the basis of this information, choose the correct word from the brackets to complete the statements:

(i) The element B would have (lower/higher) metallic character than A.

(ii) The element A would probably have (lesser/higher) electron affinity than B.

(iii) The element A would have (greater/smaller) atomic size than B.

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If the element are placed as B and then A in the 3rd period of the periodic table then

(i) The element B would have higher metallic character than A as metallic character decreases across a period.

(ii) The element A would probably have higher electron affinity than B as electron affinity increases across a period.

(iii) The element A would have smaller atomic size than B as atomic size decreases across a period.

12019

The most electronegative element from the following elements is :

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Chlorine

Reason — Chlorine is the most electronegative element among the given options because electronegativity increases left to right in a period.

22019

Fill in the blank:
In Period 3, the most metallic element is …………….. (sodium / magnesium / aluminium)

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In Period 3, the most metallic element is Sodium because metallic character decreases from left to right across a period.

32019

Give the appropriate term defined by the statement given :

The tendency of an atom to attract electrons towards itself when combined in a covalent compound.

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Electronegativity

42019

Arrange the following:

(i) Li, K, Na, H (In the decreasing order of their ionization potential)

(ii) F, B, N, O (In the increasing order of electron affinity).

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(i) H > Li > Na > K
Reason — Ionization Potential decreases as we move down the group.

(ii) B < N < O < F
Reason — Electron Affinity increases from left to right across a period.

52019

Study the extract of the Periodic Table given below and answer the questions. Give the alphabet corresponding to the element in question. Do not repeat an element. State which element :

A        
  C DE
 B     GF
         

(i) Forms an electrovalent compound with G.

(ii) Is non-metallic and has a valency of 2?

(iii) Is an inert gas?

(iv) State the ion of which element will migrate towards the cathode during electrolysis.

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(i) B forms an electrovalent compound with G.

(ii) E is non-metallic and has a valency of 2 as it belongs to group 16.

(iii) F is an inert gas as it belongs to the zero group.

(iv) A has positive ions which migrate towards cathode.

12020

The element with highest ionization potential is :

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Helium

Reason — Helium has highest ionization potential because ionization potential increases from left to right across a period and decreases down a group.

22020

Give one word or phrase for : The tendency of an atom to attract electrons to itself when combined in a compound.

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Electronegativity

32020

The question represents the elements P, Q. R and their atomic numbers.

Answer the following using only the alphabets given — P = 13; Q = 7; R = 10

(i) Which element combines with hydrogen to form a basic gas.

(ii) Which element has an electron affinity zero.

(iii) Name the element, which forms an ionic compound with chlorine.

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(i) Q combines with hydrogen to form a basic gas.

(ii) R has electron affinity zero as it's octet is complete and it is a stable element.

(iii) P forms an ionic compound with chlorine as it has +3 valency.

42020

Name the element : An alkaline earth metal present in group 2 and period 3.

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Magnesium is an alkaline earth metal which is present in group 2 and period 3.

12021-22 [Semester 2]

In the Periodic Table, elements of Period 3 are arranged in the increasing order of ionization potential as:

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Mg, Si, S, Ar

Reason — Ionisation potential increases across a period from left to right. Argon in period 3 has maximum ionisation potential, since its outermost shell is completely filled. Hence, the increasing order of ionisation potential of period 3 is - Mg < Si < S < Ar

22021-22 [Semester 2]

The tendency of an atom to attract shared pair of electrons to itself when forming a chemical bond is known as

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Electronegativity

Reason — Electronegativity is the tendency of an atom to attract shared pair of electrons to itself when forming a chemical bond.

32021-22 [Semester 2]

Elements A & B have electronic configuration : 8 & 13 respectively. The chemical formula formed between A & B will be:

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B2A3

Reason —

Electronic configuration of Element A : 8 — 2, 6
Electronic configuration of Element B : 13 — 2, 8, 3

Valency of element A : 2
Valency of element B : 3

Formula of the compound formed by the combination of A and B:

$$\begin{aligned}\overset{\phantom{3}{3}}{\text{B}} \space {\swarrow}\mathllap{\searrow} \space \overset{2}{\text{A}} \Rightarrow \underset{\phantom{2}{2}}{\text{B}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{3}{3}}{\text{A}} \\[1em] \text{B}_2\text{A}_3\end{aligned}$$

∴ Formula of the compound is B2A3

42021-22 [Semester 2]

Alkaline earth metals have the same:

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Number of valence electrons

Reason — All group 2 alkali earth metals are the elements having 2 valence electrons in their outermost electrons. Whereas, number of shells and metallic property increases down the group and ionisation potential decreases down the group.

52021-22 [Semester 2]

The electronic configuration of four elements is:

(i) W: 2,6
(ii) X: 2,8
(iii) Y: 2,8,1
(iv) Z: 2,8,7

Which pair of atoms will form a covalent compound.

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Two atoms of W

Reason — The electronic configuration of four elements :

(i) W: 2,6 — Atomic number 8
(ii) X: 2, 8 — Atomic number 10
(iii) Y: 2,8,1 — Atomic number 11
(iv) Z: 2,8,7 — Atomic number 17

Covalent bonding occurs between non-metals by sharing electrons. W needs 2 more electrons to complete its octet. So, two W atoms can share electrons with each other, forming a covalent bond
Hence, two atoms of W will form covalent bond.
However, X has completely filled outer shell, so it is not involved in covalent bond formation and bond between Y and Z is ionic.

62021-22 [Semester 2]

Element with an atomic number 19 will:

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Lose an electron & get oxidized

Reason — The element with atomic number 19 has the electronic configuration is 2, 8, 8, 1. It has 1 valence electron. It tends to lose its 1 valence electron to achieve a stable noble gas configuration. The loss of electron is defined as oxidation.

72021-22 [Semester 2]

Element with low ionization potential likely to be:

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Metal

Reason — The amount of energy required to remove a loosely bound electron from the outermost shell of an atom is known as ionisation potential. Metals have loosely held outer electrons and tend to lose electrons easily. Hence, they have low ionisation potential.

82021-22 [Semester 2]

The non-metallic properties of elements from left to right in a Periodic Table:

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Increases

Reason — As we move from left to right across a period in the periodic table the atomic size decreases, nuclear charge increases, tendency to gain electrons increases. These changes cause the non-metallic character to increase.

9(a)2021-22 [Semester 2]

The electronic arrangements of six atoms, A to F is shown below.

A: 2,5    B: 2    C: 2,6    D: 2,8,6    E: 2,8,8    F: 2,8,3

The atoms from the same group of the periodic table:

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C & D

Reason — The electronic configuration of six atoms is given below :

AtomElectronic configurationValence electrons
A2, 55
B22
C2, 66
D2, 8, 66
E2, 8, 88
F2, 8, 33

Atom C (2,6) and D (2,8,6) both have 6 valence electrons. So, they both belong to Group 16.

9(b)2021-22 [Semester 2]

The electronic arrangements of six atoms, A to F is shown below.

A: 2,5    B: 2    C: 2,6    D: 2,8,6    E: 2,8,8    F: 2,8,3

Two noble gases:

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B & E

Reason — The electronic configuration of six atoms is given below :

AtomElectronic configurationValence electrons
A2, 55
B22
C2, 66
D2, 8, 66
E2, 8, 88
F2, 8, 33

Atom B (2) and E (2, 8, 8) both have completely filled outermost electron shells. Their electronic configurations reflect stable duplet and octet arrangements. Hence, B and E are nobel gases.

9(c)2021-22 [Semester 2]

The electronic arrangements of six atoms, A to F is shown below.

A: 2,5    B: 2    C: 2,6    D: 2,8,6    E: 2,8,8    F: 2,8,3

The atom which is the most electronegative:

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C

Reason — The electronic configuration of six atoms is given below :

AtomElectronic configurationValence electrons
A2, 55
B22
C2, 66
D2, 8, 66
E2, 8, 88
F2, 8, 33

Electronegativity increases with increasing number of valence electrons. A has 5 valence electrons and C has 6. Hence, atom C has the highest electronegativity. Atom D has also has 6 valence electrons, but they are in the 3rd shell so less attraction due to increased distance. Hence, D is less electronegative than C

9(d)2021-22 [Semester 2]

The electronic arrangements of six atoms, A to F is shown below.

A: 2,5    B: 2    C: 2,6    D: 2,8,6    E: 2,8,8    F: 2,8,3

The atom which has the highest ionization potential:

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B

Reason — The electronic configuration of six atoms is given below :

AtomElectronic configurationValence electrons
A2, 55
B22
C2, 66
D2, 8, 66
E2, 8, 88
F2, 8, 33

Element B is helium, it has a completely filled outer shell, so helium has the highest ionisation potential. Element E also has completely filled outer shell, but it has 3 shells, so electrons are further away, hence it has lower ionisation energy than B.

1(i)2023

An element in period 3, whose electron affinity is zero:

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Argon

Reason — Argon belongs to period 3. It is an inert element and its octet is complete hence, it's electron affinity is zero.

1(ii)2023

An element with the largest atomic radius is:

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Lithium

Reason — The given elements belong to the second period and Lithium is the first element of second period. Atomic size decreases from left to right in a period hence, Lithium will have the largest atomic radius.

22023

State the term - The energy released when an atom in the gaseous state accepts an electron to form an anion.

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Electron affinity is the amount of energy released when an atom in the gaseous state accepts an electron to form an anion.

32023

Arrange the following:

(i) N, Be, O, C (in increasing order of non-metallic character)

(ii) P. Si, F. Be (in decreasing order of valence electrons)

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(i) Be < C < N < O

(ii) F > P > Si > Be

Reason

(i) Across a period, left to right in a periodic table, the non-metallic character increases.

(ii) The valence electrons decreases from right to left in the periodic table.

42023

Give a reason for — Ionisation potential decreases down a group.

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On moving down the group, atomic size, as well as, nuclear charge increases. However, the effect of increase in atomic size dominates over the effect of increase in nuclear charge. Hence, ionization potential decreases down the group.

1(i)2024

In the 2nd period Neon has maximum Ionization Potential because

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The outer most shell is completely filled.

Reason — The outer most shell is completely filled making it extremely stable and requiring more energy to remove an electron. Therefore, Neon has maximum Ionization Potential in the 2nd period.

1(ii)2024

Electron Affinity is maximum in :

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Br

Reason — Electron affinity tends to be highest for elements on the right side of the periodic table. Therefore, Bromine (Br) is likely to have the highest electron affinity.

22024

State the term : The tendency of an atom to pull a shared pair of electrons towards itself in a compound.

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Electronegativity

32024

Give reasons for — Inert gases do not form ions.

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Inert gases have completely filled octet which makes them extremely stable. They neither lose, nor gain electrons. Hence, they do not form ions.

42024

Arrange the following :

(a) Carbon, Fluorine, Beryllium (in decreasing order of atomic size).

(b) Potassium, Lithium, Sodium (in increasing order of ionization potential).

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(a) Beryllium > Carbon > Fluorine

(b) Potassium < Sodium < Lithium

52024

Identify the following:

(a) An element in period 1 which can be placed in both group 1 & group 17 of the Periodic Table.

(b) The element having electronic configuration 2, 8, 6.

(c) The most electronegative element of period 3.

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(a) Hydrogen

(b) Sulphur

(c) Chlorine

62024

The table shows, the electronic configuration of the atoms A, B, C & D. Answer the following:

ElementABCD
Electronic configuration2,8,8,22,62,8,72,4

(a) The formula of the compound formed between

(i) A and B
(ii) D and C

(b) Which element's exhibits catenation ?

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(a) The formula of the compounds formed are :

(i) AB is the formula of the compound formed between A and B.
Reason — A has 2 electrons in its outermost shell. B has 6 electrons in its outermost shell. To form a compound between A and B, A will donate its 2 outermost electrons to B. Hence, the formula of the compound is AB as both have 2 as valency.

(ii) DC4 is the formula of the compound formed between D and C.
Reason — D has 4 electrons in its outermost shell. C has 7 electrons in its outermost shell. Therefore, their valency is 4 and 1 respectively. So, 4 atoms of C will share their one electron each with one atom of D to form a compound. Hence, the formula of the compound is DC4.

(b) D will exhibit catenation.
Reason — Electronic configuration of D (2, 4) suggests that it is Carbon. Carbon exhibits catenation to the maximum extent due to tetra-covalency of carbon and greater strength of carbon-carbon bond.

11 Mark · Multiple Choice Questions

Assertion (A): Noble gases Ne, Ar have electron affinity zero.

Reason (R): Greater the value of electron affinity, the more electronegative is the element.

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Both A & R are true but R is not the correct explanation of A.

Reason — Noble gas elements have completely filled outer-shell. Such electronic configurations are highly stable and as such noble gases find it difficult to accept electrons. Thus electron affinity of noble gas elements is zero. Hence, the assertion (A) is true.
Elements with high electron affinity tend to strongly attract electrons, and are therefore usually more electronegative. So, greater the value of electron affinity, the more electronegative is the element. Hence, the reason (R) is true but it doesn't explain why nobel gases have zero electron affinity.

21 Mark · Multiple Choice Questions

Assertion (A): Elements with high electronegativity are usually non-metals.

Reason (R): Non-metallic atoms have high ionisation potential & tend to gain electrons.

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Both A & R are true and R is the correct explanation of A.

Reason — Electronegativity is the tendency of an atom to attract electrons in a chemical bond. Non-metals readily attract electrons and have high electronegativity. Hence, the assertion (A) is true.
Non-metals don’t lose electrons easily, and they tend to gain electrons so they have high ionization energy and are highly electronegative. Hence, the reason (R) is true and it explains why elements have high electronegativity.

31 Mark · Multiple Choice Questions

The oxide of the metallic element with three valence electrons, in its third shell is:

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Amphoteric

Reason — Three valence electrons in the third shell means the element has the configuration: 2,8,3. This corresponds to atomic number 13, which is Aluminum (Al).
Aluminum forms Al2O3 (aluminum oxide). This oxide is amphoteric, it can act as both an acid and a base.

41 Mark · Multiple Choice Questions

'ACl2' is the formula of an electrovalent solid. 'A' is likely to be in the same group in period 3, as the element given below present in period 2.

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Be

Reason — A is in period 3. The formula ACl2 suggests that A has a valency of +2, so, A is a metal that forms A2+ ions.
In Period 3, the element with valency 2 is Magnesium (Mg), it forms MgCl2, an ionic solid.

∴ Be (Beryllium) is in Group 2, period 2, the same group as Mg. Be and Mg both form +2 ions, and their chlorides have the formula ACl2.

51 Mark · Multiple Choice Questions

Metallic element 'X' in period 3, having valency 2, reacts with a non-metallic element 'Y' of the same period also having valency 2. The number of non-metallic atoms in the compound formed between 'X' & 'Y' is:

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1

Reason —

Element X : A metal in Period 3 with valency 2 will be present in group 2, so the element will be magnesium (Mg)

Element Y : A non-metal in Period 3 with valency 2 will be present in group 16, so the element will be sulphur (S).

Magnesium (Mg) with valency of 2 will form Mg2+ by the loss of 2 electrons.
Sulphur (S) with valency of 2 will form S2- by the gain of 2 electrons.

Mg2+ and S2- combine to form MgS.

∴ The number of non-metallic atoms in the compound formed between 'X' & 'Y' is 1

61 Mark · Multiple Choice Questions

State the element with the lowest electron affinity from the elements whose electronic configurations are below:

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2, 8, 8

Reason — The electronic configuration 2, 8, 8 is of argon, a nobel gas. Noble gas elements have completely filled outer-shell. Such electronic configurations are highly stable and as such noble gases find it difficult to accept electrons. Thus electron affinity of noble gas elements is zero.

71 Mark · Multiple Choice Questions

Non-metallic elements have:

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High ionisation potential

Reason — Non-metals possess relatively small atomic radii and their valence electrons are strongly attracted by the nucleus. Consequently, a large amount of energy is required to remove an electron, giving them high ionization energy.

81 Mark · Multiple Choice Questions

The electronic configuration of the element which has the largest atomic size is:

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2, 8, 1

Reason — Atomic radius increases down a group because each successive period adds a new electron shell, and it decreases from left to right across a period owing to increasing nuclear charge.

  • Configurations 2, 1 and 2, 8, 1 belong to Group 1.
  • Element with electronic configuration (2, 8, 1) is one period below lithium, so it possesses an additional electron shell and therefore a larger atomic radius.
  • The remaining configurations (2, 8, 5) and (2, 8, 7) lie further to the right in Period 3, where atomic size is smaller.

Hence, the element with configuration 2, 8, 1 has the largest atomic size among the choices given.

1Additional & High Order Thinking Questions

Rewrite the incorrect statements only by rectifying the incorrect word/s in the statement.

(a) Periodic table is based on the fundamental property atomic weight.

(b) Elements in the periodic table are arranged in seven horizontal rows called 'groups', which ends with an element having one electron in outermost shell.

(c) Period numbers i.e., 1, 2, 3 signifies the no. of electron shells of an element e.g. period 3 element 'Mg' has 2 shells.

(d) Across a period from left to right the no. of electron shells increases by one & the valence electron remains same.

(e) Group numbers i.e., 1, 2, 3 signifies the number of electron shells of an element.

(f) Down a sub-group, the valence electrons & the number of electron shells remains same.

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The corrected statements are given below:

(a) The periodic table is based on the fundamental property atomic number.

(b) Elements in the periodic table are arranged in Seven horizontal rows called periods, which ends with an element having a full outermost shell.

(c) Period numbers i.e., 1, 2, 3 signify the number of electron shells of an element e.g. period 3 element 'Mg' has 3 shells.

(d) Across a period from left to right, the no. of electron shells remains same and the number of valence electrons increases.

(e) Group numbers i.e., 1, 2, 3 signify the number of valence electrons of an element.

(f) Down a sub-group, the valence electrons remain the same & the number of electron shells increases.

2Additional & High Order Thinking Questions

Correct the order of elements in period 1 to 3 of the periodic table & state their correct electronic configurations.

PeriodGroup 1Group 2Group 13Group 14Group 15Group 16Group 17Group 18 (O)
1H      He
2Li [2,1]CONBBeFNe
3NaAlSiMgSClPAr
4KCa    BrKr
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PeriodGroup 1Group 2Group 13Group 14Group 15Group 16Group 17Group 18 (O)
1H      He
2Li [2,1]BeBCNOFNe
3NaMgAlSiPSClAr
4KCa    BrKr
3(a)Additional & High Order Thinking Questions

Give reason — Noble gases are considered, unreactive elements.

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Noble gases are largely unreactive because their outermost electron shells are completely filled (helium has a stable duplet of two electrons, while the other noble gases have an octet of eight electrons). With a full valence shell, they have no strong tendency to gain, lose, or share electrons, so they rarely take part in chemical reactions.

3(b)Additional & High Order Thinking Questions

Give reason — In a sub-group the chemical properties of elements remain similar.

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Elements belonging to the same group have the same number of valence (outermost) electrons, so their outermost electronic configurations are alike. As chemical properties depend mainly on this outer electronic configuration, the elements in a group exhibit similar chemical properties.

3(c)Additional & High Order Thinking Questions

Give reason — Halogens in group 17 are strong oxidising agents.

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Halogens have seven valence electrons and therefore need only one additional electron to attain a stable octet. Their very high electron affinity and electronegativity make them readily accept an electron from other substances, so they act as powerful oxidising agents.

3(d)Additional & High Order Thinking Questions

Give reason — Atomic radii is considered a periodic property, exhibiting periodicity.

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When the elements are arranged in order of increasing atomic number, the atomic radius shows a regular, repeating pattern: it generally decreases from left to right across a period (because of increasing nuclear charge) and increases down a group (due to the addition of new electron shells). Because this variation repeats in each successive period, atomic radius is classified as a periodic property.

4Additional & High Order Thinking Questions

Complete the definitions of the periodic properties given below :

(a) Atomic size- the distance between—
(b) Ionisation potential- the amount of energy required—
(c) Electron affinity- the amount of energy released—
(d) Electronegativity- the tendency of an atom to attract—
(e) Metallic character- of an element is exhibited when an atom of the element loses—
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(a) Atomic size — The distance between the centre of the nucleus of an atom and its outermost shell.

(b) Ionisation potential — The amount of energy required to remove a loosely bound electron from the outermost shell of an isolated gaseous atom.

(c) Electron affinity — The amount of energy released when an atom in the gaseous state accepts an electron to form an anion.

(d) Electronegativity — The tendency of an atom to attract electrons to itself when combined in a compound.

(e) Metallic character — Metallic character of an element is exhibited when an atom of the element loses one or more electrons when supplied with energy.

6Additional & High Order Thinking Questions

State the following

(i) Physical properties of elements which exhibit periodicity

(ii) Nature of hydroxides of elements which exhibit periodicity

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(i) Physical properties of elements which exhibit periodicity are :

  1. Density
  2. Melting point
  3. Boiling point

Across a period — Density and melting point of elements increases gradually and then slightly decreases thereafter

Down a group — Density increases gradually, melting point and boiling point of elements decreases gradually

(ii) Nature of hydroxides of elements which exhibit periodicity is given below

  1. Across a period — The nature of hydroxides changes from strongly basic to amphoteric.
  2. Down a group — The nature of hydroxides changes from less basic to strongly basic, due to increasing atomic size and metallic character.
1Identify the following

The alkali metal in period 2 and the halogen in period 3.

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Lithium, chlorine.

2Identify the following

The noble gas having duplet arrangement of electrons.

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Helium

3Identify the following

The noble gas having an electronic configuration 2, 8, 8.

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Argon

4Identify the following

The number of electron shells in elements of period 3.

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3

Reason — The number of shells present in an atom determines it's period. Hence, element of period 3 will have 3 shells.

5Identify the following

The valency of elements in group 1[IA].

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One

Reason — Group number signifies the number of valence electrons of an element. Hence valency of group 1[1A] elements will be one.

6Identify the following

The metals present in period 3 and the non-metals present in period 2.

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Metals present in period 3 are Na, Mg and Al.
Non-metals present in period 2 are C, N, O and F.

7Identify the following

The group whose elements have zero valency.

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Group 18 (Inert gases group)

Reason — The group 18 elements have 2 or 8 valence electrons and are stable elements hence have zero valency.

8Identify the following

The non-metal in period 3 having a valency 1.

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Chlorine

9Identify the following

The formula of the hydroxide of the element having electronic configuration 2, 8, 2.

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Mg(OH)2

10Identify the following

The formula of the hydride of the halogen in period 3.

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HCl

11Identify the following

The formula of the sulphite of the element in period 3, group 1 [IA].

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Na2SO3

12Identify the following

The element in period 3 which does not form an oxide.

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Argon

Reason — Electronic configuration of argon is 2, 8, 8 and so it's octet is complete and is stable and it does not form oxide.

13Identify the following

The bonding [i.e. electrovalent or covalent] of the oxide of the element in period 3 group 16 [VIA].

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Covalent

Reason — As the combining atoms i.e., S and O are non-metals and they both have high electron affinity hence they share two pairs of valence electrons in order to complete their octet and attain a stable state and hence form covalent bond.

14Identify the following

The character of the hydroxide of the element in period 3 group 13 [IIIA].

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Amphoteric

Reason — As we move from left to right in periodic table, the basic character decreases and acidic character increases. Group 13 [IIIA] lies in the middle of the periodic table, hence it has amphoteric nature.

15Identify the following

A light element in period 3 Which is a stable metal and a light metal.

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Magnesium (Mg)

Reason — Magnesium is a light element in Period 3 that is considered a stable and light metal because it has a low atomic mass, moderate reactivity, and forms a protective oxide layer that prevents rapid corrosion, making it chemically stable.

16Identify the following

The element with the least atomic size from carbon, nitrogen, boron and beryllium.

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Nitrogen

Reason — As atomic size decreases across a period (from left to right) and nitrogen lies at the right side of the periodic table, hence it has least size.

17Identify the following

The element, from the elements Li, Na, K, having the least number of electron shells.

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Li (Lithium)

Reason — As the number of shells increases as we move down a group and Li lies in period 2 and is at top among the given elements hence has the least number of shells.

18Identify the following

The element from the elements C, O, N, F, having the maximum nuclear charge.

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F (Fluorine)

Reason — Nuclear charge increases across a period (from left to right) and fluorine lies at the right side of the periodic table hence it has maximum nuclear charge.

19Identify the following

The element from the elements Be and Mg having a lower nuclear charge.

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Be (Beryllium)

Reason — Nuclear charge increases down a group and among Be and Mg, Be is on top of Mg hence Be will have lower nuclear charge.

20Identify the following

The element from the elements fluorine and neon having a higher electron affinity.

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Fluorine

Reason — Electron affinity of neon is zero because it is an inert element hence fluorine has higher electron affinity amongst the two.

21Identify the following

The period and group to which the element 'X' with electronic configuration 2, 8, 8, 2 belongs.

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Group 2, period 4

Reason — Period is determined by the number of shells of the element and group is determined by the number of valence electron hence, element X will belong to group 2 and period 4 because it has 4 shells and 2 valence electrons.

22Identify the following

The more electronegative element from the elements Ar, S, Cl of period-3.

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Cl (Chlorine)

Reason — As electronegativity increases across a period (from left to right) and Ar is an inert element hence, Cl will have the highest value of electronegativity among the given elements.

23Identify the following

The element with the largest atomic size from the elements of period 1, 2 and 3.

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Sodium

Reason — As atomic size decreases across a period (from left to right) and increases down a group hence sodium will have the largest atomic size from the elements of period-1, 2 and 3 because it is placed in period 3 and group 1 and is at the lower left side among the given elements.

24Identify the following

The element with the highest ionization potential from the elements of period 1, 2 and 3.

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Helium

Reason — As ionization potential increases across a period (from left to right) and decreases down a group hence helium will have the highest ionization potential among the elements of period-1, 2 and 3 because it is placed in period 1 and group 18 and is at the top right side of the periodic table.

25Identify the following

The element from the elements Li, Na, K which has maximum metallic character.

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K (Potassium)

Reason — As metallic character increases down a group hence K will have maximum metallic character among the given elements.

1Complete the Following Statements

Periods are ............... [5, 6, 7] horizontal rows of elements in the periodic table and an element with three electron shells and two electrons in it's valence shell belongs to period ............... [6, 3, 1] and group ............... [3, 6, 2].

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Periods are 7 horizontal rows of elements in the periodic table and an element with three electron shells and two electrons in it's valence shell belongs to period 3 and group 2.

2Complete the Following Statements

Across a period the valence electrons ..............., while down a subgroup they ............... [remain same / increase by 1]

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Across a period the valence electrons increase by 1 while down a subgroup they remain same.

3Complete the Following Statements

Across a period, the electropositive character ..............., and down a group the electronegative character ............... [increases/decreases].

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Across a period, the electropositive character decreases and down a group the electronegative character decreases.

4Complete the Following Statements

Elements at the extreme left of the modern periodic table are ............... reactive, while elements on the extreme right [group 18 (0)] are ............... reactive [least/un/most].

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Elements at the extreme left of the modern periodic table are most reactive, while elements on the extreme right [group 18 (0)] are unreactive.

5Complete the Following Statements

Elements of group 1 [IA] are strong ............... [oxidizing/reducing] agents since they are electron ............... [acceptors/donors].

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Elements of group 1 [IA] are strong reducing agents since they are electron donors.

6Complete the Following Statements

The element in group 17 [VIIA] which is a liquid at room temperature is ............... [F, Cl, Br, I].

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The element in group 17 [VIIA] which is a liquid at room temperature is Br.

7Complete the Following Statements

Periodicity in properties is observed in elements after definite intervals due to similar ............... [electronic configuration, number of valence electrons, atomic numbers] of elements.

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Periodicity in properties is observed in elements after definite intervals due to similar electronic configuration.

8Complete the Following Statements

Across a period the nature of oxides and hydrides varies from ............... to ............... [acidic/basic] while the strength of oxy-acids ............... [decreases/increases] from left to right.

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Across a period the nature of oxides and hydrides varies from basic to acidic while the strength of oxy-acids increases from left to right.

9Complete the Following Statements

Nuclear charge of an atom is the ............... [negative/positive] charge on the nucleus of an atom, equivalent to the atomic ............... [number/mass] of an atom.

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Nuclear charge of an atom is the positive charge on the nucleus of an atom, equivalent to the atomic number of an atom.

10Complete the Following Statements

Atomic size of neon is ............... [more/less] than the atomic size of fluorine.

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Atomic size of neon is more than the atomic size of fluorine.

11Complete the Following Statements

Atomic size across a period ............... [increases/decreases] with increase in nuclear charge of the element.

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Atomic size across a period decreases with increase in nuclear charge of the element.

12Complete the Following Statements

With increase in nuclear charge the nuclear attraction for outer electrons ............... [increases/decreases], hence ionization potential ............... [increases/decreases].

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With increase in nuclear charge the nuclear attraction for outer electrons increases, hence ionization potential increases.

13Complete the Following Statements

Increase in nuclear charge of an atom ............... [decreases/increases] the tendency of the atom to lose electrons.

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Increase in nuclear charge of an atom decreases the tendency of the atom to lose electrons.

14Complete the Following Statements

Elements with stable electronic configuration e.g. neon have an electron affinity value of ............... [1, 0, -1].

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Elements with stable electronic configuration e.g. neon have an electron affinity value of 0 .

15Complete the Following Statements

An atom with a small atomic radii takes up electrons ............... [less/more] readily than an atom with a large radii.

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An atom with a small atomic radii takes up electrons more readily than an atom with a large radii.

16Complete the Following Statements

If combining atoms of a compound have nearly similar electronegativities the bond between them is ............... [electrovalent/covalent].

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If combining atoms of a compound have nearly similar electronegativities the bond between them is covalent

17Complete the Following Statements

Elements with low electronegativity are usually ............... [metallic/non-metallic].

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Elements with low electronegativity are usually metallic.

18Complete the Following Statements

An atom is said to be a non-metal, if it ............... [gains/loses] one or more electrons.

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An atom is said to be a non-metal, if it gains one or more electrons.

19Complete the Following Statements

Atoms with ............... [small/large] atomic radii and ............... [high/low] ionization potential tend to gain electrons.

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Atoms with small atomic radii and high ionization potential tend to gain electrons.

20Complete the Following Statements

Element 'X' in period 3 has high electron affinity and electronegativity. It is likely to be a ............... [metal/non-metal].

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Element 'X' in period 3 has high electron affinity and electronegativity. It is likely to be a non-metal.

21Complete the Following Statements

Element 'B' in period 2 is to the right of the element 'A'.
Element 'B' is likely to be ............... [more/less] non-metallic in character than element 'A'.

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Element 'B' in period 2 is to the right of the element 'A'.
Element 'B' is likely to be more non-metallic in character than element 'A'.

22Complete the Following Statements

Element 'Z' in sub-group 2[IIA] is below element 'Y' in the same sub-group. The element 'Z' will be expected to have ............... [higher/lower] atomic size and ............... [more/less] metallic character than 'Y'

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Element 'Z' in sub-group 2[IIA] is below element 'Y' in the same sub-group. The element 'Z' will be expected to have higher atomic size and more metallic character than 'Y'

23Complete the Following Statements

Argon in period 3 is likely to have a ............... [larger/smaller] atomic size than chlorine and it's electron affinity value would be ............... [greater/lesser/zero] compared to chlorine.

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Argon in period 3 is likely to have a larger atomic size than chlorine and it's electron affinity value would be zero compared to chlorine.

24Complete the Following Statements

Across a period — Atomic size and metallic character ............... while I.P., E.A., E.N. and non-metallic character ............... and nuclear charge ............... [increases/decreases].

Down a group — Atomic size and metallic character ............... while I.P., E.A., E.N. and non-metallic character ............... and nuclear charge ............... [increases/decreases].

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Across a period — Atomic size and metallic character decreases while I.P., E.A., E.N. and non-metallic character increases and nuclear charge increases.

Down a group — Atomic size and metallic character increases while I.P., E.A., E.N. and non-metallic character decreases and nuclear charge increases.

1Give reasons for the Following

Give reasons for the following:

In the same period or subgroup a gradual change in a particular property may be seen.

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In the same period or sub group a gradual change in particular property may be seen because physical and chemical properties are periodic function of their atomic number and as the elements are arranged in an increasing order of atomic number in the periodic table hence we see a gradual change.
In other words, it is due to the gradual change in electronic configuration in the arranged elements.

2Give reasons for the Following

Give reasons for the following:

Atomic size of group 18 [0 group] elements is more than the atomic size of group 17 [VIIA] elements.

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The outer shell of group 18 [0 group] elements is completely filled. Due to this force of repulsion is maximum. The effect of nuclear pull over the valence shell electrons is not seen. Hence, Atomic size of group 18 [0 group] elements is more than group 17 [VIIA] elements.

3Give reasons for the Following

Give reasons for the following:

Ionization potential increases with increase in nuclear charge of the elements.

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As nuclear charge increases, the nuclear attraction on the outer most electron increases and the outer electron is more firmly held. Therefore, ionization potential increases.

4Give reasons for the Following

Give reasons for the following:

Electron affinity of noble gas elements is zero.

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Noble gas elements have completely filled outer-shell. Such electronic configurations are highly stable and as such noble gases find it difficult to accept electrons. Thus electron affinity of noble gas elements is zero.

5Give reasons for the Following

Give reasons for the following:

Phosphorus, sulphur and chlorine are electronegative elements of the periodic table.

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Phosphorus, Sulphur and Chlorine are the rightmost elements of period 3 in the periodic table. Across a period from left to right electronegativity increases as nuclear charge increases and atomic size decreases. This makes Phosphorus, Sulphur and Chlorine electronegative elements of the periodic table.

6Give reasons for the Following

Give reasons for the following:

Sulphur is placed in group 16 [VIA], chlorine in group 17[VIIA] but argon in group 18 [0 group] of the periodic table.

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Elements are arranged in increasing order of atomic number in the periodic table. The elements placed in group 16 have 6 electrons in the outer most shell, elements of group 17 have 7 valence electrons and the group 18 elements have 8 valence electrons.

Electronic configurations of Sulphur (S), Chlorine (Cl) and Argon (Ar) are:

S = 2, 8, 6
Cl = 2, 8, 7
Ar = 2, 8, 8

With 6 valence electrons S is placed in Group 16, Cl with 7 valence electrons is placed in Group 17 and Ar with 8 valence electrons is in Group 18.

7Give reasons for the Following

Give reasons for the following:

Fluorine is the most electronegative element of the periodic table.

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Fluorine is placed in period 2 group 17(VIIA) in the modern periodic table i.e., it occupies the upper right hand corner of the periodic table. Along a period from left to right electronegativity increases and down a group from top to bottom it decreases. Hence, Fluorine being the topmost and rightmost element in its group and period is the most electronegative element of the periodic table.

8Give reasons for the Following

Give reasons for the following:

Atoms with large atomic radii and low ionization potential are more metallic in nature.

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Metals have the tendency to lose one or more electrons i.e., they are are electropositive in nature. Atoms with large atomic radii and low ionization potential can easily lose one or more electrons because the nuclear pull on the outer electrons is less. Therefore, these atoms are more metallic in nature.

9Give reasons for the Following

Give reasons for the following:

A decrease in ionization potential of an element leads to a decrease in non-metallic character of the element.

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When there is a decrease in ionization potential then the tendency to lose electron increases. This results in a decrease in non-metallic character and increase in metallic character.

10Give reasons for the Following

Give reasons for the following:

Atomic size decreases across a period but increases down a group of the periodic table.

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Across a period from left to right, nuclear charge increases. This decreases the size of the atom because the electrons are then attracted towards the nucleus with a greater force thereby bringing the outermost shell closer to the nucleus.
Down a group, the number of shells and nuclear charge both increase. But increase in the number of shells dominate over increase in nuclear charge. This increase in the number of shells increases the size of an atom because the distance between the outermost shell and the nucleus increases.

1Unit Test Paper I — Periodic Table

In period 2, element 'A' is to the right of element 'B'

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  1. The element 'A' would probably have a smaller atomic size than 'B'
  2. The element 'B' would probably have lower ionization potential than 'A'.
  3. The element 'A' would have higher electron affinity than 'B'.
  4. Nuclear charge of element 'B' would be less than element 'A'.
  5. If an element 'C' had a low electronegativity and ionization potential it would have more tendency to lose electrons.
2Unit Test Paper I — Periodic Table

With reference to period 3 of the periodic table — State :

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  1. The element with electronic configuration 2, 8, 7 will form ionic bonds with metals and with non-metal it will form covalent bond.
  2. The element with electronic configuration is 2, 8, 4 is Si and with chloride it forms SiCl4.
  3. The alkaline earth metal in the period 3 is Mg and it's oxide is basic in nature (i.e. MgO is basic is nature).
  4. The number of electrons in the penultimate shell of the element with valency -1 is 8.
  5. The element is Magnesium and electronic configuration is (2, 8, 2)
3Unit Test Paper I — Periodic Table

With reference to group 1 [IA] of the periodic table – fill in the blanks with the correct word:

The elements are ............... [light/heavy] ............... [metals/non metals] since their atomic size is ............... [large/small]. The energy binding the atoms is ............... [high/low] and hence the elements have ............... [high/low] melting points. The melting points of the elements ............... [increases/decreases] down the subgroup. The electropositive character ............... [increases/decreases] down the subgroup and the elements are strong ............... [reducing/oxidizing] agents. The element with electronic configuration 2, 8, 1 will have ............... [higher/lower] electron affinity and ............... [smaller/larger] atomic size than the element with electronic configuration 2, 1.

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The elements are light metals since their atomic size is large. The energy binding the atoms is low and hence the elements have low melting points. The melting points of the elements decreases down the subgroup. The electropositive character increases down the subgroup and the elements are strong reducing agents. The element with electronic configuration 2, 8, 1 will have lower electron affinity and larger atomic size than the element with electronic configuration 2, 1.

4Unit Test Paper I — Periodic Table

Match the elements in column 'X' with the correct group they belong from column 'Y'

    X    Y
1: Element with atomic number 19A: Group 18 [0 group]
2: Element with electronic configuration 2B: Group 16 [VI A]
3: Element with a valency of -2C: Group 1 [IA]
4: Element 'P' which loses 3 electrons to form a cationD: Group 17 [VII A]
5: Element 'Q' in period-3 which has the highest electron affinityE: Group 13 [III A]
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XY
1: Element with atomic number 19A: Group 1 [IA]
2: Element with electronic configuration 2B: Group 18 [0 group]
3: Element with a valency of -2C: Group 16 [VI A]
4: Element 'P' which loses 3 electrons to form a cationE: Group 13 [III A]
5: Element 'Q' in period-3 which has the highest electron affinityD: Group 17 [VII A]
5.1Unit Test Paper I — Periodic Table

Give reasons for the following:

Occurrence of characteristic properties of elements takes place at definite intervals in the modern periodic table.

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After definite intervals of atomic number, similar valence shell electronic configuration occurs. Properties of elements depend upon their electronic configuration. As in the modern periodic table, the elements are arranged in increasing order of their atomic numbers hence we observe the occurrence of characteristic properties of elements at definite intervals.

5.2Unit Test Paper I — Periodic Table

Give reasons for the following:

Properties of elements are periodic functions of their atomic numbers and not atomic weights.

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Atomic number of an element is equal to the number of protons (or electrons in case of a neutral atom). Physical and chemical properties of elements depend on the number of electrons and their arrangement. Thus, properties of elements are periodic function of their atomic numbers and not atomic weights.

5.3Unit Test Paper I — Periodic Table

Give reasons for the following:

Atomic size of an element depends on the nuclear charge of that element.

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Nuclear charge is the positive charge present in the nucleus of an atom and when there is an increase in nuclear charge then the atomic size decreases because the electrons are attracted towards the nucleus with a greater force thereby bringing the outer most shell closer to the nucleus.

5.4Unit Test Paper I — Periodic Table

Give reasons for the following:

Down a group electronegativity should increase with increase in nuclear charge but it is seen that the electronegativity decreases.

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On moving down a group both atomic size and nuclear charge increases but the increase in atomic size dominates over increase in nuclear charge hence Electronegativity decreases on moving down a group.

5.5Unit Test Paper I — Periodic Table

Give reasons for the following:

If combining atoms have nearly similar electro­negativities the bond between them is covalent.

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If two combining atoms have almost similar electronegativities then transference of electrons cannot take place and the atoms share their valence electron equally with each other hence covalent bond is formed by mutual sharing of electrons.

6Unit Test Paper I — Periodic Table

Arrange the following elements as per the guidelines in brackets.

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  1. Na > Mg > P > Cl
  2. Li < C < N < F
  3. Na < Al < S < Cl
  4. Li < C < O < F
  5. He < Ne < Ar

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